Pythagora's Theorem
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Alchemy Mindworks
The previous proof is Bhaskara's (An ancient hindu mathematician). The following is from
James Abram Garfield (1831-1881), 20th. president of the U.S. (assasinated)
The triangle ABC is rectangle (right angle at A).
Draw CD perpendicular to BC in C, such that CD = BC.
Draw a line parallel to AB, containig D. This line shall meet the line containing A and C
in (say) Z.
Now, you can easily see that ABC and CDZ are equal (congruent) triangles, with AB = CZ,
and AC = DZ.
Call a = BC = CD, b = AC = DZ, and c = AB = CZ.
Note that ABDZ is a trapecium with area
A = (AC+CZ)(AB+ZD)/2 = (b+c)(c+b)/2 ......(1)
Also, A is the sum of the areas of ABC, CDZ and BCD. That is A = bc/2 + bc/2 + a.a/2
.......................(2)
Equating (1) and (2) -and simplifying-, we are done.